Balancing Redox Reactions
Fe 2+ + Cr → Fe + Cr 3+ Solution. We start by writing the two half reactions. Chromium is being oxidized, and iron is being reduced: Cr → Cr 3+ oxidation Fe 2+ → Fe reduction. Then we include the appropriate number of electrons on the proper side to balance the charges for each reaction: Cr → Cr 3+ + 3e − Fe 2+ + 2e − → Fe